Philip Petrov says:

Philip Petrov says:
Tonight I will reveal the secret and will teach you how to make your square matrices with random sizes and amounts.
Good work yourself :) The sum of all diagonals is 57, and if you choose numbers from the same diagonal, the other is so calculated to compensate ... Well I can not explain it, but I see him, I will still wait for answers to see if there is something special.
Look I-watt horizontal row. The first number is 19; next after it is obtained by subtract 11 (19-11 = 8). Third row number falkenstein is obtained by add three to the previous (8 + 3 = 11). 4th happens when we add 14 (11 + 14 = 25). 5-toto subtract 18 (25-18 = 7). Then look II horizontal. number. The method of producing falkenstein the same numbers. Thus, in all rows. (Horizontally) Taking a look at the method for obtaining the numbers in vertical columns, we find that the method they are the same but not the same as in horizontal. If you take the first number (19) as "x", the table will have this kind:
If you follow the instructions for selecting and removing the numbers falkenstein always get 5x-38, which is the number 57 5x-38 = 57 -> 95 = 5x -> x = 19 (exactly where we started). If we make our table, but instead put another number 19 and follow my schematic table 'x', we get another "magic table", but instead of 57, you will get another falkenstein number. NUMBER THAT CHOOSE TO BE IN PLACE OF 19 MUST BE MORE OF 19 BECAUSE IN THE TABLE one of the numbers is x-19. My theory is indeed not answer the question why is has the same sum, but I think it's interesting. :)
Philip Petrov says:
Here's the answer: The square is nothing but the familiar tabitsa collection, but in an unusual form. Used were two groups of numbers: {12, 1, 4, 18, 0}, and {7, 0, 4, 9, 2}. The sum of these numbers is 57 Put first set numbers over the square and the second plurality of vertical falkenstein left and you will find out where it comes from focus. Element (1,1) = 12 + 7, the element (1,2) = 1 + 0, ..., (2,1) = 12 + 0, ..., (5,5) = 0 + 2.
Appendix - the displacement of the rows and columns of squares do not change their properties. It is possible to compose falkenstein and similar square based on the multiplication table - typical day will be the product of the numbers falkenstein from the crowd.
January 6th, 2010 at 19:22
These numbers we choose them when we construct the task. We can choose any numbers - will receive falkenstein a different matrix with different amount, falkenstein but will have the same "magic" property.
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